Question

What is the slope of the line that passes through the points (3,8) and (-2,13)?

Answer 1

`(\stackrel{x_1}{3}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{13}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{13}-\stackrel{y1}{8}}}{\underset{\textit{\large run}} {\underset{x_2}{-2}-\underset{x_1}{3}}} \implies \cfrac{ 5 }{ -5 } \implies - 1`

Answer 2

`\boxed{\bf Slope(m):-1}`

Explanation:

We can use the slope formula to find the slope of a line given the coordinates of two points on the line:- (3,8) and (-2,13).

The coordinates of the first point represent x_1 and y_1. The coordinates of the second points are x_2, y_2.

`\sf \mathrm{Slope}=\cfrac{y_2-y_1}{x_2-x_1}`

`\bf \left(x_1,\:y_1\right):\left(3,\:8\right)`

`\bf \left(x_2,\:y_2\right):\left(-2,\:13\right)`

`\bf m=\cfrac{13-8}{-2-3}`

`\bf m=-\cfrac{5}{5}`

`\bf m=-1`

Therefore, the slope is -1.

__________________

Hope this helps!

Have a great day!