Question

A rectangle has a length of 5x+2 and a width of 3x - 1. If x=10, what is the perimeter and area?

Answer 1

Area of rectangle = 1508

Perimeter of rectangle = 162

Explanation:

Now we have to,

→ find the perimeter and area.

→ where x = 10.

Perimeter of rectangle is,

→ P = 2 × (L + W)

→ P = 2 × (5(10) + 2 + 3(10) - 1)

→ P = 2 × (50 + 2 + 30 - 1)

→ P = 2 × 81

→ [ P = 162 ]

Area of rectangle will be,

→ A = L × W

→ A = (5(10) + 2) × (3(10) - 1)

→ A = (50 + 2) × (30 - 1)

→ A = 52 × 29

→ [ A = 1508 ]

Hence, these are the values.

Answer 2

Perimeter = 162 units

Area = 1508 square units

Explanation:

Given expressions:

• Length = 5x + 2
• Width = 3x - 1

If x = 10, then:

• Length = 5(10) + 2 = 52
• Width = 3(10) - 1 = 29

The formula for the perimeter of a rectangle is:

• P = 2(w + l)

where w is the width and l is the length.

Therefore, the perimeter of the rectangle is:

`\implies \sf P = 2(29 + 52)`

`\implies \sf P = 2(81)`

`\implies \sf P = 162\;units`

The formula for the area of a rectangle is:

• A = w · l

where w is the width and l is the length.

Therefore, the area of the rectangle is:

`\implies \sf A=29 \cdot 52`

`\implies \sf A=1508\;square\;units`