Answer:
See below, and note the interpretation of the question.
Explanation:
See the attached image for a graph of all the lines and points.
1. Write an equation in slope-intercept form of the line given the slope=" 1/4 pass through (-2,1).
1. Look for an equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x is zero).
We are given the slope, so use that for m: y = (1/4)x + b.
We need a value of b that forces the line through point (-2,1). This can be done by entering the point into the above equation and solving for b:
y = (1/4)x + b
1 = (1/4)*(-2) + b [for (-2,1)]
1 = -0.5+ b
b = 1.5
The equation is y = (1/4)x + 1.5
2. Write an equation in slope-intercept form of the line that passes through (0,4) and (5,19)
1. Look for an equation of the form y=mx+b
2. Determine the slope by calculating the Rise and Run of the two given points:
Going from (0,4) to (5,19):
Rise = 19-4 = 15
Run = 5 - 0 = 5
Rise/Run, or slope, m = (15/5) or 3
The equation with the slope of 5:
y = 5x+b
3. To find b, enter either of the 2 points into the equation and solve for b:
y = 5x+b
4 = 5*(0)+b for (0,4)
b = 4
The equation is y=5x+4
3. Write a linear function f with the given values.
Are the expressions written correctly? I see f and g. I'll assume the forst two are meant to be f, and the last two a new function, g(x).:
a. f(0) = 2, f(2) = -3
b. g(-4) = -5, g(3) = - 1.
These results supply us with 2 points for each function [line]:
f: (0,2) and (2,-3)
g: (-4,-5) and (3,-1)
We can use these two points to find the slope for lines f and g:
f: (0,2) and (2,-3)
Rise = -3 - 2 = -5
Run = 2 - 0 = 2
Slope = (-5/2) or -2.5
The equation for f is y = (-2.5)x + b
Enter one of the 2 points to find b:
y = (-2.5)x + b
y = (-2.5)*(0) + b for (0,2)
2 = b
The equation for f is f(x) = -2.5x+2
Do the same for g:
(-4,-5) and (3,-1)
Rise = (-1 - (-5)) = 4
Run = (3 - (-4)) = 7
Slope = 4/7 or 0.571
y = 0.571x + b
Substituting point (3,-1) and solving for b:
-1 = 0.571*(3) + b
b = -2.71
The equation for g is g(x) = 0.571c-2.71
See the attached image.