Question

5. A bullet accelerates at 5.8 x 10 m/s from rest as it travels the 0.80 m of the

rifle barrel.
a
How long was the bullet in the barrel?
b. What velocity does the bullet have as it leaves the barrel?

Answer 1

Below

Step-by-step explanation:

d = 1/2 a t^2

.80 = 1/2 ( 5.8 x 10^?) t^2

( I think you left off the exponent...and acceleration has units m/s^2 ...not m/s)

t = .166 s

v = at = 58 x .166= 9.63 m/s