Question

4. Consider the following information about a group of 143 FCC students:GenderRight-handedLeft-handedTotalFemale631578Male511465Total11429143If one person is randomly selected from the group, what is the probability that this student is female or left-handed?

Answer 1

First, let find the probability that is a female student.

The total of students is 143.

The total of female students is 78.

The P(female) =78/143 = 6/11

Now, let's find the probability that is left-handed.

The total of left-handed students is 29.

The P(left-handed) = 29/143

Now, the probability that the student is female or left-handed.

The "or" rule of probability tells us that when we have an "or", its means that we add the probabilities.

So P(female or left-handed) = P(female) + P(left-handed)

Replace the values.

P(female or left-handed) = 6/11 + 29/143 -174/1573 = 0.63