Question

One of the legs of a right triangle measures 7 cm and the other leg measures 17 cm. Find the measure of the hypotenuse. If necessary round to the nearest tenth.

Answer 1

`\huge\boxed{\sf H=18.4\ cm}`

Explanation:

Given that,

Base = 7 cm

Perpendicular = 17 cm

Hypotenuse = H

Using Pythagoras theorem.

`(Hypotenuse)^2=(Base)^2+(Perpendicular)^2\\\\(H)^2=(7)^2+(17)^2\\\\(H)^2=49+289\\\\(H)^2=338\\\\Take \ square\ root \ on \ both\ sides\\\\√((H)^2) =√(338) \\\\H=18.4\ cm\\\\\rule[225]{225}{2}`