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What are the solutions of 6t − 1 ≥ 4t + 13?

User Utsav
by
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2 Answers

4 votes

Answer:

Inequality Form: t ≥ 7

Interval Notation: [ 7, ∞ }

Explanation:

1) Move all terms that contain "t" to the left side of the inequality by subtracting 4t from both sides.

a) 6t – 1 – 4t ≥ 13, THEN subtract 4t from 6t

b) 2t – 1 ≥ 13

2) Move terms that do not contain "t" to the right side of the inequality:

a) ADD 1 to both sides ––> 2t ≥ 13 + 1

b) ADD 13 and 1 ––> 2t ≥ 14

3) Divide each term by 2, then simplify:

= 2t/2 ≥ 14/2

4) Simplify the left side:

t = 14/2

5) Simplify the right side:

t ≥ 7

ANSWER:

Inequality Form:
t ≥ 7

Interval Notation: [ 7, ∞ }

User Todd Stout
by
6.6k points
4 votes

Answer:

t ≥ 7

Explanation:

6t - 1 ≥ 4t + 13 ( subtract 4t from both sides )

2t - 1 ≥ 13 ( add 1 to both sides )

2t ≥ 14 ( divide both sides by 2 )

t ≥ 7

User JoeButler
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7.7k points