Question

Two cars A and B are initially at the same position. Car A starts moving at constant speed of 4m/s. If car B starts moving at constant speed of 8m/s, 2 seconds later after car A moved, where does car B overtakes car A? A. 12m B. 30m C. 16m D. 24m​

Answer 1

16 m

Step-by-step explanation:

(4 m/s)(t + 2 s) = (8 m/s)t

4t + 8 = 8t

8 = 4t

t = 8/4 = 2 sec

This means that after Car A has traveled for 4 sec, Car B catches up to it after it has traveled 2 s (having left 2 s after Car A).

Where do they meet up:

d = rt

Car B: d = (8 m/s)(2 s) = 16 m

Car A: d = (4 m/s)( 2 s + 2 s) = 16 m **always check both equations to make sure your answer is correct