Question

A car drives 215 KM East, and then 45 KM North what is the magnitude of the crisis appointments round your answer to the nearest

whole number?

Answer 1

So, the magnitude of the crisis appointments to the nearest whole number is 220 km.

Introduction and Formula Used

Hi! Here I will help you to discuss the displacement of a movement. Unlike distance which is a scalar quantity, displacement is a vector quantity. Then, we can define the distance as the shortest distance from two points of two or more movements. In this case, the car's motion is from east to north. Remember that the angle formed between east and north is mutually perpendicular (90°). So, we can calculate the magnitude of the displacement that occurs in two mutually perpendicular movements with this equation:

`\boxed{\sf{\bold{s = √((x_1)^2 + (x_2)^2)}}}`

With the following condition:

• s = the displacment
• 
  `\sf{x_1}` = the distance of first movement
• 
  `\sf{x_2}` = the distance of second movement

Problem Solving

We know that:

• 
  `\sf{x_1}` = the distance after first movement = 215 km to the east.
• 
  `\sf{x_2}` = the distance after second movement = 45 km to the north.

What was asked:

• s = the displacment or crisis appointment = ... km

Step by step:

`\sf{s = √((x_1)^2 + (x_2)^2)}`

`\sf{s = √((245)^2 + (45)^2)}`

`\sf{s = √(46,225 + 2,025)}`

`\sf{s = √(48.250)}`

`\sf{\bold{s \approx 219,66 \: km}}`

Conclusion

So, the magnitude of the crisis appointments to the nearest whole number is 220 km.