183k views
1 vote
A baker sells bread for $3 a loaf and rolls for $1 each. The baker needs to sell $27 worth of baked goods by

the end of the day.
Graph the linear equation 3b + r = 27, where b is the number of loaves of bread sold and r is the
number of rolls sold.

A baker sells bread for $3 a loaf and rolls for $1 each. The baker needs to sell $27 worth-example-1
User Duyue
by
6.8k points

1 Answer

4 votes

Answer:

4 loaves of bread

Explanation:

Cost of 1 loaf of bread = $3

Cost of 1 roll = $1

The baker needs to sell both items and it should be worth $24.

To find the linear equation,

Suppose, the baker sells

x

loaves of bread and

y

rolls.

Then the total cost of the sales has to be $24.

So, the linear equation will be:

3

x

+

1

y

=

24

.......................(A)

Now, it is given that the baker sold 12 rolls and we need to know how many loaves he has to sell.

For that, replace the

y

in equation (A) with 12 as

y

represents number of rolls sold.

Then the new equation becomes:

3

x

+

1

×

12

=

24

0r

3

x

=

24

12

or

3

x

=

12

Solving for

x

,

x

=

12

3

=

4

loaves

User Mikal
by
7.1k points