Question

A line passes through the point (1, -9) and has a slope of 5.

Write an equation in slope-intercept form for this line.

Answer 1

y = 5x - 14

Explanation:

The equation of a line in slope-intercept form is y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

Given that the line passes through the point (1, -9) and has a slope of 5, we can use point-slope form to write the equation of the line. Point-slope form is written as: y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, and m is the slope of the line.

We know that the line passes through the point (1, -9) and has a slope of 5, so we can substitute these values into the point-slope form:

y - (-9) = 5(x - 1)

Simplifying, we get:

y + 9 = 5x - 5

Now we can add 9 to both sides to get:

y = 5x - 14

So the equation of the line in slope-intercept form is y = 5x - 14

We can confirm that the point (1,-9) belongs to the line by substitute the values x =1 and y = -9 into the equation y = 5x - 14, if the equation holds true then the point belongs to the line.

Answer 2

y = 5x - 14

Explanation:

The slope-intercept form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept (the point at which the line crosses the y-axis).

Given that the line passes through the point (1, -9) and has a slope of 5, we can use the point-slope form of a line, which is y - y1 = m(x - x1)

Substituting the point and slope we have:

y - (-9) = 5(x - 1)

y + 9 = 5x - 5

Now we can solve for y by adding 9 to both sides of the equation:

y = 5x - 14

So the equation in slope-intercept form for the line that passes through the point (1, -9) and has a slope of 5 is:

y = 5x - 14