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√x = √3x
What is the solution to the equation above?

2 Answers

3 votes

Answer:


\sf \: x = (1)/(3) \: (or) \: x = 0

Explanation:

The equation given is,

→ √x = √3x

Now the value of x will be,

→ √x = √3x

→ x = (√3x)²

→ x = 3x²

→ 3x² = x

→ 3x² - x = 0

→ (3x - 1)(x) = 0

→ 3x - 1 = 0 || → x = 0

→ 3x = 0 + 1 || → [ x = 0 ]

→ 3x = 1 ||

→ [ x = 1/3 ] ||

These are the values of x.

User Cayhorstmann
by
7.2k points
3 votes

Answer:


x=0,\;x=(1)/(3)

Explanation:

Given equation:


√(x)=√(3)x

Square both sides:


\implies \left(√(x)\right)^2= \left(√(3)x\right)^2


\implies x= \left(√(3)\right)^2 \cdot \left(x\right)^2


\implies x=3x^2

Subtract x from both sides:


\implies x-x=3x^2-x


\implies 0=3x^2-x


\implies 3x^2-x=0

Factor out the common term x:


\implies x(3x-1)=0

Apply the zero-product property:


\implies x=0


\implies 3x-1=0 \implies x=(1)/(3)

User Sssheridan
by
7.9k points