Question

Solve for a: a 3 - 4. =0 a. a+2

Answer 1

D) a=6

Step-by-step explanation

`(3)/(a)-(4)/(a+2)=0`

Step 1

make tha addition

`\begin{gathered} (3)/(a)-(4)/(a+2)=\frac{3(a+2)-4a}{a\text{ (a+2)}} \\ (3)/(a)-(4)/(a+2)=(3a+6-4a)/(a^2+2a) \\ (3)/(a)-(4)/(a+2)=(6-a)/(a^2+2a) \\ \text{then} \\ (6-a)/(a^2+2a)=0 \end{gathered}`

Step 2

solve the new equation

`\begin{gathered} (6-a)/(a^2+2a)=0 \\ \text{Multiply both sides by }(a^2+2a) \\ (a^2+2a)\cdot(6-a)/(a^2+2a)=0\cdot(a^2+2a) \\ 6-a=0 \\ subtract\text{ 6 in both sides} \\ 6-a-6=0-6 \\ -a=-6 \\ \text{Multiply both sides by -1 } \\ -1-a=-6\cdot-1 \\ a=6 \end{gathered}`

I hope this helps you