Answer:
altitude ≈ 23 cm
Explanation:
since the triangle is isosceles then the altitude AD is the perpendicular bisector of BC , so
BD =
BC = 7 cm
using Pythagoras' identity in right triangle ABD
AD² + BD² = AB²
AD² + 7² = 24²
AD² + 49 = 576 ( subtract 49 from both sides )
AD² = 527 ( take square root of both sides )
AD =
≈ 23 cm ( to the nearest whole number )
then the altitude is approximately 23 cm