Answer:
How many couples bought tickets?
50
Explanation:
s + 2c = 196 Eq. 1
6s + 10c = 1076 Eq, 2
s = single tickets
c = couple tickets
From Eq. 1:
s = 196 - 2c Eq. 3
Replacing Eq. 3 in Eq. 2:
6(196-2c) + 10c = 1076
(6*196 + 6*-2c) + 10c = 1076
(1176 - 12c) + 10c = 1076
1176 - 2c = 1076
1176 - 1076 = 2c
100 = 2c
c = 100/2
c = 50
From Eq. 3:
s = 196 - 2c
s = 196 - 2*50
s = 196 - 100
s = 96
Check:
From Eq. 2:
6s + 10c = 1076
6*96 + 10*50 = 1076
576 + 500 = 1076