Explanation:
Given equations are
2x+3y=13 ....(1)
4x+y=11 .....(2)
multiply the equation (2) by 3, we get
⇒12x+3y=33 .....(3)
Subtract equation (1) from (3) to eliminate y, we get
12x+3y=33
2x+3y=13
− − −
10x=20
⇒x=2
Put this value in equation (1), we get
⇒2(2)+3y=13
⇒4+3y=13
⇒3y=9
⇒y=3
∴ the solution is x=2,y=3.