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Question 29 of 40What is the length of the longest side of a triangle that has vertices at (-3,-1), (-3, 4), and (9, -1)

User Snf
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1 Answer

11 votes
11 votes

Vertices(-3, -1), (-3, 4) and (9, -1)


\begin{gathered} d=\sqrt[]{(-3+3)^2+(-5)^2} \\ d=\sqrt[]{25} \\ d=5 \\ \\ d=\sqrt[]{(12)^2(0)}^2=\sqrt[]{144}=12 \\ d=\sqrt[]{(12)^2(5)^2}^{}=\sqrt[\square]{144+25}=\sqrt[]{169}=13 \end{gathered}

The longest side is 13

Question 29 of 40What is the length of the longest side of a triangle that has vertices-example-1
User Anjan Kant
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