Question

What is the molarity of the solution produced when 85.6 g of hydrochlorie acid

(HCI) is dissolved in sufficient water to prepare 0.385 L of solution?

Answer 1

The molarity of the solution is 25.5 M.

To calculate the molarity, we can use the formula: Molarity = (moles of solute/volume of solution). The molar mass of HCl is 36.5 g/mol, so we can calculate the number of moles present in 85.6 g of HCl: 85.6 g HCl/36.5 g/mol = 2.35 mol. We can then plug that value into our formula: Molarity = (2.35 mol/0.385 L) = 25.5 M.