Question

An object is launched into the air at 60 feet per second from a platform 80 feet high given by the equation f(t) = -16t2+60t+80.

What is the maximum height?

Answer 1

Below

Explanation:

For the Quadratic Equation - 16t^2+ 60t + 80

the max value will occur at t = - b/2a = -60 / (2 * -16) = 1.875 s

use this value f t in the equation to find max height = 136.25 ft