Question

Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot 2(x2 + 6x + 9) = –3 + 9

Answer 1

(2x + 3)(x - 1) = 0
x = (-b ± √(b^2 - 4ac))/ 2a, where a = 2, b = 12, and c = -3.
2x^2 + 12x = 3
(6/2)^2 = 9
2x^2 + 12x + 9 - 9 = 3 - 9
factor out the 2x^2 + 12x + 9 = 0