Question

HELP, QUICK!!! 19 POINTS up for the ANSWER

On a road trip, a family drives 200 miles the first day and 350 miles per day each remaining day. How many additional days, d, will they travel to reach a distance of 1,600 miles?

Part A
Write an equation to represent this situation.
_______+_______d=_________ (The number of underscores isn't for the number of digits I just put them to show an empty space.)

Part B
Solve the equation. How many total days does the family travel?

(please answer each part of the question and label your answer. Thanks!)

Answer 1

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Explanation:

Part A: To record an equating defining this position, we can start by canny the total distance camouflaged in d supplementary days. Since the kin drives 350 5 per epoch each surplus era, the total distance marked in d supplementary days is 350d. Adding the beginning 200 5 compelled on the first epoch, the equating enhances:200 + 350d = 1,600Part B: To resolve the equating and find the total number of days the offspring will travel, we need to detach the changeable d. We can start by subtracting 200 from two together hands of the equating:350d = 1,600 - 200350d = 1,400Next, we separate two together parts of the equating by 350 to resolve for d:d = 1,400 / 350d = 4Therefore, the kin will travel for an supplementary 4 days to reach a total distance of 1,600 5.