182k views
2 votes
The population of a city was 34,000 at the beginning of 1937. Its

population steadily increased by 6.8% every year from 1937 to 1997.
Which of these is the closest to the population of the city at the end of
1970?

User Nikjohn
by
8.6k points

1 Answer

5 votes

Answer:

298078.228074

Explanation:

we add 6.8% of the population to the city each year

city population in year x + 1 = city population in year x + 6.8% of city population in year x = city population in year x + 0.068 * city population in year x = 1 * city population in year x + 0.068 * city population in year x = 1.068 * city population in year x

we multiply the population by 1.068 each year to get the next year's population

thus, over a period of y years, we would multiply the population by 1.068 y times.

start = 34000 in 1937

difference in years = 1970 - 1937 = 33

final amount = 34000 * 1.068 33 times = 34000 * 1.068^33 = 298078.228074

User Satyajit Rout
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories