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Determine the equation of a straight line passing through (-1,3) and parallel to the line whose equation is 3x-5y=10.

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5 votes

Answer:

y = (3/5)x+3.6

Explanation:

Let's look for an equation of the standard form: y=mx+b, where m is the slope and b is the y-intercept (the value of y when x is 0). Parallel lines have the same slope, m. Next, rearrange the reference line to standard format:

3x-5y=10

-5y = -3x + 10

y = (3/5)x + 2

Now we can easily find the slope. The slope of the reference line is (3/5). That will also be the slope of the parallel line, so we can write:

y = (3/5)x + b

We need a value of b that will shift the line so that it touches point (-1,3) . ["passes through"]. Enter that point into the above equation and solve for b:

y = (3/5)x + b

(3) = (3/5)*(-1) + b for point (-1,3)

3 = -(3/5) + b

-(3/5) = 3-b

-b = -3 - (3/5)

b = 3+(3/5)

b = (18/5), or 3.6

The equation becomes y = (3/5)x+3.6

See the attached graph.

[Parallel lines have a lot in common. Too bad they'll never meet.]

Determine the equation of a straight line passing through (-1,3) and parallel to the-example-1
User Rohit Jagtap
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