Question

Particles q1, q2, and 9 are in a straight line.

Particles q1 = -5.00 • 10-6 C,92 = +2.50 • 10-6 C, and 93 = -2.50 • 10-6 C. Particles qi and q, are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m. What is the net force on q2?

Answer 1

0.27475 N

Step-by-step explanation:

To find the net force acting upon q2, we need to find the force exerted by q1 to q2 and the force exerted by q3 to q2, and to do that we should apply the formula

`F = |(kq_(1)q_(2) )/(r^(2) )|`

where in k is coulomb's constant (
`8.99*10^9 (Nm^(2))/(C^(2))`)

q1 and q2 are the charges

and r is the distance between the two charges.

Finding the force exerted to q2 by q1:

`F = |((8.99*10^(9) * (-5*10^(-6)) * (2.5*10^(-6)))/((0.500)^(2))|`

F = 0.4995 N

q1 would be attracted to q2, so it would go to the right, so it's a positive force

Finding the force exerted to q2 by q3:

`F =|((8.99*10^(9))*(-2.5*10^(-6))*(2.5*10^(6)))/(0.250^(2))|`

F = 0.22475 N

q3 would be attracted to q2, so it would go to the left, so it's a negative force

F = -0.22475N

Add-up the forces: 0.4995 + (-0.22475) = 0.27475 N