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A baker sells bread for $6 a loaf and rolls for $2 each. The baker needs to sell $60 worth of baked goods by

the end of the day.
Use the graph to approximate how many loaves of bread the baker must sell if 24 rolls are sold, where b
is the number of loaves of bread and r is the number of rolls.
Number of
rolls sold
6b+2r=60

User Natchiketa
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1 Answer

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Answer: We can start solving this problem by using the information given in the equation 6b + 2r = 60. This equation represents the total cost of the bread and rolls sold, with 6b representing the cost of the bread (6 dollars per loaf) and 2r representing the cost of the rolls (2 dollars each). The goal is to find the value of b, the number of loaves of bread sold.

We can use the information that the baker sold 24 rolls. If we substitute this value into the equation, we get:

6b + 2(24) = 60

Next, we can simplify the equation by substituting in the value of 24 for r:

6b + 48 = 60

Now we can subtract 48 from both sides of the equation to find the value of b:

6b = 12

Finally, we can divide both sides of the equation by 6 to find the value of b:

b = 12/6 = 2

So the graph suggests that the baker must sell approximately 2 loaves of bread if 24 rolls are sold.

We can check this by substituting this value in the equation to make sure that it works and total cost of the bread and rolls sold is $60

6(2) + 2(24) = 60, which is true

It is important to note that this is an approximation based on the information given, and it is possible that the baker may have sold a different number of loaves of bread while selling 24 rolls.

Explanation:

User Mbartn
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