Question

2Al + 3CuCl2 = 2AlCl3 + 3Cu (copper (ii) chloride + aluminum = aluminum chloride + copper) Examine your balanced equation. So if you had 0.26 moles of Aluminum foil, then how many exact moles of copper (II) chloride would be needed for stoichiometry

Answer 1

Answer: .39 Moles would be needed.

Explanation: The mole-to-mole ratio of Copper (ll) chloride to Al is 3/2. We can tell by looking at the coefficients of the reactants. Al has a coefficient of 2 and CuCl2 has a coefficient of 3. The ratio of CuCl2 to Al is 3:2 or 3/2. We multiply this ratio by the number of moles of Al which .26 to find how much we need of CuCl2. Now figure out how many moles of AlCl3 you would produce from .26 moles of Al.