Answer: ±1.4
Explanation:
f(x)=ax^2+c
The graph passes through (2,2) and (-2,2)
Vertex:(0,-2)
f(x)=ax^2-2
4a-2=2
4a=4
a=1
f(x)=x^2-2
if f(x)=0
x^2-2=0
x^2=2
x=±=±1.414
x=±1.4
7.9m questions
10.6m answers