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Find the equation of the line that passes through the point (6,-2) and is parallel to the line 5x+3y

User Crews
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1 Answer

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Answer: y=(-5/3)x+8

Step-by-step explanation: earrange 5x+3y=6 in slope intercept form

y=mx=b

5x+3y=6

3y=6-5x

y=2-(5x)/3

then slope for a line parallel is -5/3

Use point slope form y-y1=m(x-x1)

plug un values of (x,y) = (6,-2)

and m=-5/3

y-y1=m(x-x1)

y-(-2)=(-5/3)(x-6)

y+2=(-5/3)x+10

y=(-5/3)x+10-2

y=(-5/3)x+8 <-- solution

User Froston
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