Question

Morgan cycled from Town A to Town B at an average speed of 15 km/h. She reached Town B at 6 P.M. If she increased her average speed to 20 km/h, she would arrive at 5 P.M. At what time would she arrive at Town B if she cycled at an average speed of 25 km/h?

Answer 1

Answer: Morgan will arrive at Town B at 5pm - 36 minutes = 4:24pm if she cycled at an average speed of 25km/h.

Step-by-step explanation: To solve this problem, we can use the formula: distance = speed x time.

We know that at 15km/h, Morgan reaches Town B at 6pm, and at 20km/h, she reaches Town B at 5pm.

We can use this information to find the distance between Town A and Town B and the time it takes to travel this distance at 25 km/h.

First, let's find the distance between Town A and Town B:

distance = speed x time

distance = 15 km/h x time

time = distance / 15 km/h

time = (distance / 15) hours

Since we know that when Morgan travel at 15km/h to reach town B at 6pm, we can use the time to calculate the distance:

time = 6pm - 5pm = 1hour

distance = 15 km/h x 1 hour = 15 km

Next, we can use this distance and the new speed 25km/h to calculate the arrival time:

time = distance / speed

time = 15 km / 25 km/h = 0.6 hours = 36 minutes

So, she will arrive at Town B at 5pm - 36 minutes = 4:24pm if she cycled at an average speed of 25km/h.

Please note that this calculation is assuming that the distance between Town A and Town B is a constant, and assuming that the time of arrival at 15km/h and 20km/h are accurate.