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HELPPP AGAIN PLEASEE. What is the equation of the line that passes through the point (-6,5) and has a slope of -3/2?

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Answer:

y - y1 = m(x - x1)

y - 5 = -3/2 [x - (-6) ]

2 (y - 5) = 2 × -3/2 [x - (-6) ]

2y - 10 = -3 [x + 6]

2y - 10 = -3x - 18

2y- 10 + 3x + 18 = 0

2y + 3x -10 + 18 = 0

2y + 3x + 8 = 0

Explanation:

I stated the formula to find the equation of the line . Then replaced the y1 and x1 with -6 and 5 respectively. I multiplied the whole equation by the LCM, which is 2. Group the whole equation to the left and equate it to 0. Then group like terms and solve. The final answer is the equation of the line

User Andrea Scarafoni
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