211k views
4 votes
Select the correct answer. What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)? A. x2 + y2 − 4x + 2y + 1 = 0 B. x2 + y2 + 4x − 2y + 1 = 0 C. x2 + y2 + 4x − 2y + 9 = 0 D. x2 − y2 + 2x + y + 1 = 0 Reset Next

1 Answer

3 votes

Answer B)

Explanation:

( x + 2 )² + ( y - 1 )² = r²

( - 4 + 2 )² + ( 1 - 1 )² = r²

4 = r², than we will plug in to a formula:

( x + 2 )² + ( y - 1 )² = 4

x² + 4 x + 4 + y² - 2 y +1 = 4

x² + y² + 4 x - 2 y + 1 = 0

User Pokepetter
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories