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G(x)=x^2+3x-3
What are the zeros of the function?

User Abskmj
by
5.1k points

1 Answer

13 votes

Answer:

(-3+
√(21)) /2, (3+
√(21)) / 2 which is approx -3.791 and 0.791

Explanation:

i used the quadratic formula: [-b± sq rt (b² - 4ac) / 2a]

in this problem, a = 1, b = 3, and c = -3

User Terriann
by
5.2k points