Question

PLS I WILL FAAAIIIIL

Factor the following expressions completely. Show and check all work on your own paper. 4x2+4x+1

Answer 1

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

let's solve ~

`\qquad \sf  \dashrightarrow \: 4x {}^(2) + 4 x + 1`

`\qquad \sf  \dashrightarrow \: 4 {x}^(2) + 2x + 2x + 1`

`\qquad \sf  \dashrightarrow \: 2x(2x + 1) + 1(2x + 1)`

`\qquad \sf  \dashrightarrow \: (2x + 1) (2x + 1)`

`\qquad \sf  \dashrightarrow \: (2x + 1)`

The required (factored) expression will be :

• (2x + 1)²

Answer 2

The factorised form of the expression given 4x² +4x +1 according to the task content is; (2x+1) (2x+1).. What is the factorised form of the expression given in the task content? It follows from the task content that the given expression is; 4x² +4x +1. Hence, it follows from factorisation convention that the expression above can be rewritten as;. 4x² +2x +2x +1

Explanation: