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An irregular polygon is shown below:

The area of the irregular polygon is ____ square units.

An irregular polygon is shown below: The area of the irregular polygon is ____ square-example-1
User Viru
by
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2 Answers

2 votes

Answer:

20

Explanation:

To get the area of this irregular polygon, we have to turn the irrelgular polygon into 2 shapes. (Imagine a line drawn from the corner/wall that separates the unit 1 and 4 units down the bottom of the shape. I don't rlly know how to explain it sorry).

First we calculate the first rectangle which is simple, you just have to multiply! 3x4= 12.

Then for the second one, we have to subtract. Basically, 8 units minus 4 units is equal to 4 units meaning that our lenght is four units. Then 3 units minus 1 unit is equal to 2 units which is our width. (i'm deeply sorry if I couldn't explain it the best) Now we just do 4x2=8.

Now we just add 12 and 8 which gives us 20!

User Horst Gutmann
by
7.7k points
3 votes

Answer:

20 square units

Explanation:

you can separate this irregular polygon into 2 rectangles:

Rectangle 1 (bigger): 3 Units X 4 Units = 12 square units

Rectangle 2 (smaller): 2 Units X 4 Units = 8 square units

Add the 2 areas: 12+8 square units = 20 square units

An irregular polygon is shown below: The area of the irregular polygon is ____ square-example-1
User Drnextgis
by
7.3k points