Answer:
A. Function 1 has the lowest minimum value, and its coordinates are (−1, −3).
Explanation:
To find the minimum value for f(x), set its first derivative to 0 and solve for x.
First derivative of f(x) is
f'(x) = 8x + 8 + 0 = 8x + 8
Setting this equal to 0 gives
8x + 8 = 0
8x = -8
x = -1
Plugging in this value for x in 4x² + 8x + 1 gives
f(x) = 4(-1)² + 8(-1) = 4 · 1 - 8 + 1
= 4 - 8 + 1
-4 + 1
= -3
So minimum for f(x) occurs at (-1, -3)
For g(x) the minimum is 0 and is at x = -1
So f(x) has minimum of -3 at x = -1
g(x) has minimum of 0 and occurs at x = -1
Answer:
A. Function 1 has the lowest minimum value, and its coordinates are (−1, −3).