Question

The product of 3 and a number equals the sum of 16 and a number.

Answer 1

6,7,8 is are variable

Answer 2

The numbers can be either -8,-7,-6, or 6, 7, 8.

n(n−1)(n+1)=16(n−1+n+n+1)

⟹n(n2−1)=16×3n

⟹n(n2−1)n=48nn

⟹(n2−1)−48=48−48

⟹n2−49=0

⟶(n−7)(n+7)=0

n can be 7 or −7 , so the numbers can be either −8,−7,−6

Or

6,7,8

Explanation: