Answer:
2.58 m/s
Step-by-step explanation:
To determine the theoretical speed at which the golf ball must have left the floor, you can use the principle of conservation of energy, which states that the total energy in a closed system remains constant. In this case, we can use the fact that the ball's potential energy changes as it rises and falls.
First, we know that the efficiency of the ball is 61.0%, so we can assume that 39% of the energy is lost as heat, sound, etc. We can calculate the initial kinetic energy (Ei) of the ball as:
Ei = Efficiency * (Initial Potential energy - Final Potential energy)
Ei = 0.61 * (0.444 - 0.271) = 0.119J
Now, we can use this value to calculate the velocity (Vi) of the ball as it left the floor, by using the equation of kinetic energy:
Ei = 0.5 * m * Vi^2
Where:
m = mass of the ball = 0.0453 kg
Vi = velocity of the ball when it left the floor
By substituting the values in the equation we get:
0.119 = 0.5 * 0.0453 * Vi^2
Solving for Vi:
Vi = sqrt(0.119 / (0.5 * 0.0453))
Vi ≈ 2.58 m/s
So, the theoretical speed with which the ball must have left the floor is approximately 2.58 m/s
Keep in mind that this is a theoretical speed and there may be a variance with real-world observations.