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What is the y-intercept of a line that passes through the points (2, -2.5) and (4, -2)?

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Answer:

Explanation:

To find the y-intercept, we can use the slope-intercept form of a linear equation which is y = mx + b, where m is the slope of the line, and b is the y-intercept.

Since the line passes through the points (2, -2.5) and (4, -2), we can use the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

To find the slope(m) we can use the rise over the run formula ,

m = (y2 - y1) / (x2 - x1) = (-2 - (-2.5)) / (4 - 2) = -0.5

then we can substitute the values in point-slope form

y - (-2.5) = -0.5 (x - 2)

And now we can use x = 0,

y = -0.5(0-2) -2.5 = 1.5

so the y-intercept of the line is 1.5

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