Question

At what ordered pair will the function

f ( x ) = √ x + 2 - 2

begin on the coordinate plane?

( ? , ?)

Answer 1

Answer:(-2,-2)

Explanation:

The radical has a value of 0 when x = -2. At that point, the function value is ...

f(-2) = √(-(-2)-2) -2 = √(0) -2

f(-2) = -2