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Find the first term in geometric sequence if the 11th term is -160 and the ratio is -1/3​

1 Answer

5 votes

Answer:

-9447840

Explanation:

You want the first term of a geometric sequence whose 11th term is -160 and whose common ratio is -1/3.

N-th term

The n-th term of a geometric sequence is ...

an = a1·r^(n-1)

where a1 is the first term and r is the common ratio.

Using the given values, we have ...

-160 = a1·(-1/3)^(11 -1)

a1 = (-160)·(-3)^10 = -9447840

The first term is -9447840.

User Casey Marshall
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