Question

Yea I do it on my own but it was a goodFactor:

Answer 1

Answer::

`7m^2n^2(2m^6n^3-1)`

Explanation:

Given the expression:

`14m^8n^5-7m^2n^2`

7m²n² is a common factor of the two terms.

Factor it out by dividing each of the terms to get the remainders:

`14m^8n^5-7m^2n^2=7m^2n^2\mleft((14m^8n^5)/(7m^2n^2)-(7m^2n^2)/(7m^2n^2)\mright)`

This then gives:

`\begin{gathered} =7m^2n^2\mleft((7*2* m^2* m^6* n^2* n^3)/(7m^2n^2)-(7m^2n^2)/(7m^2n^2)\mright) \\ =7m^2n^2((7m^2n^2*2* m^6* n^3)/(7m^2n^2)-1) \\ =7m^2n^2(2m^6n^3-1) \end{gathered}`

The factored form of the expression is:

`7m^2n^2(2m^6n^3-1)`