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7•e^.1t =47 express the solution as a logarithmic in base e
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7•e^.1t =47 express the solution as a logarithmic in base e

User PeteUK
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Answer:

The value of t is 19.04

Explanation:


7e^(0.1t) = 47\\


e^(0.1t) = (47)/(7)

take log both sides :


ln(e^(0.1t)) = ln((47)/(7)) \\0.1t = 1.9042\\t = (1.9042)/(0.1)\\t = 19.04

User Chris Hatton
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