Answer:
4|x|y²√(3yz)
She forgot the absolute value sign on x, and she left out the exponent on y.
Explanation:
Step 1 is correct.
x may be positive, zero, or negative.
√x is always non-negative. To assure that √x² is non-negative, √x² = |x|.
√16 = 4
√3 = √3
√x² = |x|
√y² × √y² = √y^4 = y²
Since y² is always non-negative, there is no need for absolute value sign.
√y^4 = y²
Answer should be
4|x|y²√(3yz)