Question

A 28.94 L quantity of neon gas is at 20.0°C when some punk bunny turns thdown to 10.0°C. What is the new volume of the neon gas?Record the number value of your answer to two decimal places.

Answer 1

27.95L

Explanations:

According to Charle's law, the volume of a given mass of a gas is directly proportional to absolute temperature provided that the pressure is constant. Mathematically;

`\begin{gathered} V\alpha T \\ V=kT \\ k=(V_1)/(T_1)=(V_2)/(T_2) \end{gathered}`

where

V1 and V2 are the initial and final volume respectively

T1 and T2 are the initial and final temperature respectively (in Kelvin)

Given the following parameters

`\begin{gathered} V_1=28.94L \\ T_1=20.0^0C+273=293K \\ T_2=10.0^0C+273=283K \end{gathered}`

Required

Final volume V₂

Substitute the given parameters into the formula to have:

`\begin{gathered} V_2=(V_1T_2)/(T_1) \\ V_2=(28.94*283)/(293) \\ V_2=(8190.02)/(293) \\ V_2=27.95L \end{gathered}`

Hence the new volume of the neon gas is 27.95L