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find equation of the line passing through (4,8) and parallel to the line 3x+y=17( Please give workout)

User Aq
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1 Answer

3 votes

Answer:

y = -3x +20

Explanation:

Equation of line: y =mx + b

Where m is the slope and b is the y-intercept.

3x + y = 17

Write the above equation in y = mx +b form.

y = -3x + 17

m = -3

Parallel lines have same slope.

So, slope of the required line is (-3).

y = -3x + b

This line is passing through (4,8). Substitute in the above equation and find the value of 'b'.

8 = -3*4 + b

8 = -12 + b

8 + 12 = b

b = 20

Equation of the line:


\sf \boxed{ y = -3x + 20}

User Oleh Demkiv
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8.3k points