y = 3/2x - 9/2
The equation of the line that passes through the points (4,-3) and (2,0) can be found using the point-slope form of a linear equation. The point-slope form of a linear equation is y-y1=m(x-x1), where m is the slope of the line and (x1,y1) is a point on the line.
To calculate the slope, we will use the formula m = (y2-y1)/(x2-x1). In this equation, (x1,y1) = (4,-3) and (x2,y2) = (2,0). Substituting these values into the slope formula, we get m = (0-(-3))/(2-4) = 3/(-2) = -1.5.
Now that we have the slope, we can plug the point (4,-3) and the slope (-1.5) into the point-slope form of a linear equation to get y-(-3)=-1.5(x-4). Simplifying this equation, we get y+3=-1.5x+6, which is the equation of the line that passes through the points (4,-3) and (2,0).