Answer:
a.LiF
b.BeO
c.MgF2
d.AlCl3
e.Be3N2
Step-by-step explanation:
So, the main thing with chemical formulas is making sure that the cation and anion's charges will cancel out if you add the total sum of charges together.
For A, halogens only form -1 charge ions, so F will have to be F-. Lithium, being a group 1 element, will form an ion of Na+. Therefore, the formula is NaF.
For B, Beryllium is a Group 2 element that forms +2 charges, while Group 16 elements like O form -2 charges. Therefore, BeO would work as the sum of charges will equal zero.
For C, Magnesium is a Group 2 element, so it has a +2 ion, while fluorine is a halogen, so a -1 charge for the F- ion. So, you need two F- ions to balance out one Mg2+ ion. So, it is MgF2
For D, Aluminum is a Group 13 element, which can form +3 charges. Therefore, Al can form a +3 charge, so that means for Cl- (recall it is a halogen,) it needs three Cl- ions to cancel one Al3+ ion. So, it is AlCl3.
For E, Group 15 elements like N form -3 ions, so the ion for nitrogen is N3-. Beryllium is a Group 2 element, so it is Be2+. The common multiple of 3 and 2 is 6, so you need to find a way to have a +6 and -6 charge. So, three Be2+ ions (totaling a net charge of +6) need to cancel with two N3- ions (again a net charge of -6) to form the compound. Therefore, it is Be3N2.