Question

Need with this … substitution method..

Answer 1

The solution is the point (-3,2)

Explanation:

x + 2y = 1 Subtract 2y from both sides

x + 2y - 2y = 1 - 2y

x = 1 - 2y Substitute 1 - 2y in for x in the second equation and solve for y.

5x -4y = -23

5(1 - 2y) -4y = -23 Distribute the 5

5(1) - 5(2y) - 4y = -23

5 -10y - 4y = -23 Combine like terms

5 -14y = -23 Subtract 5 from both sides

5 -5 - 14y = -23 -5

-14y = -28 Divide both sides by -14

`(-14y)/(-14)` =
`(-28)/(-14)`

y = 2

Solve for y

x + 2y = 1 Substitute in 2 for y and solve for x

x + 2(2) = 1

x + 4 = 1 Subtract 4 from both sides

x + 4 - 4 = 1 - 4

x = -3

The solution is the point (-3,2)

Check:

2 + 2y = 1

-3 + 2(2) = 1

-3 + 4 = 1

1 - 1 checks

5x - 4y = -23

5(-3) - 4(2) -23

-15 - 8 = -23

-23 = -23