Question

Can someone please help me with this? and also help me understand how to do it I have a test this Friday.

Answer 1

`T=2\pi \sqrt{\cfrac{L}{g}}\implies \cfrac{T}{2\pi }=\sqrt{\cfrac{L}{g}}\implies \cfrac{T}{2\pi }=\cfrac{√(L)}{√(g)}\implies T√(g)=2\pi √(L) \\\\\\ √(g)=\cfrac{2\pi √(L)}{T}\implies (√(g))^2=\left( \cfrac{2\pi √(L)}{T} \right)^2\implies g=\left( \cfrac{2\pi √(L)}{T} \right)^2 \\\\\\ g=\cfrac{(2\pi √(L))^2}{(T)^2}\implies g=\cfrac{4\pi ^2L}{T^2}`