213k views
4 votes
Last week, Alex took 90 selfies and Vic took 75 selfies. Today,

they each decided that some of these selfies were not very good
and deleted them. Alex deleted three times as many selfies
as Vic. Now, Alex has half as many selfies as Vic. How many
selfies did Alex delete?

User Dan Klos
by
7.9k points

2 Answers

5 votes

Final answer:

Alex originally had 90 selfies. Vic deleted 'x' selfies, and Alex deleted three times as many. Solving the equation given by the conditions, we find Alex deleted 63 selfies.

Step-by-step explanation:

Let us denote the number of selfies Alex deletes as 3x and the number of selfies Vic deletes as x. Originally, Alex had 90 selfies, so after deletion, he will have 90 - 3x selfies left. Vic had 75 selfies and deletes x, ending up with 75 - x selfies.

According to the problem, after deletion, Alex has half as many selfies as Vic. This can be expressed as 90 - 3x = ½ (75 - x). This equation simplifies to 90 - 3x = 37.5 - 0.5x. Taking 'x' terms to one side of the equation and constants to the other gives us 2.5x = 52.5, which simplifies to x = 21.

Therefore, Alex deleted 3x = 3 × 21 = 63 selfies.

User Dreamzboy
by
6.9k points
3 votes

Answer:

Alex deleted 37.5 selfies

Step-by-step explanation:

Let X be the number of selfies that Vic deleted.

Alex deleted 3X selfies.

After deleting selfies, Alex has 90-3X selfies left.

Vic has 75-X selfies left.

Since Alex has half as many selfies as Vic, we can set up the equation: 90-3X = (75-X)/2

Multiplying through the parentheses on the right side, we get: 90-3X = 75-X/2

Combining like terms, we get: 2X = 15

Dividing both sides by 2, we get: X = 7.5

Since X represents the number of selfies that Vic deleted, Vic deleted 7.5 selfies.

Since Alex deleted 3 times as many selfies as Vic, Alex deleted 37.5 = <<37.5=22.5>>22.5 selfies.

User Eric Meadows
by
7.8k points